23 lines
406 B
Python
23 lines
406 B
Python
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import numpy as np
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for n in [3,5,10,100,1000]:
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A = np.zeros((n,n))
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x = np.zeros((n,1))
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y_c = np.zeros((n,1))
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for i in range(0,n):
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x[i] = i+1
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y_c[i] = (i+1) * n;
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for j in range(0,n):
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A[i,j] =(i+1) / (j+1)
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y = A@x
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if n == 3 or n == 5:
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print(x)
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print(A)
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print(y)
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print("Fuer n =",n,":",np.linalg.norm(y - y_c))
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