praktikum_wissenschaftliche.../uebung_02/main_matrix.c
2023-11-22 19:51:30 +01:00

65 lines
1.4 KiB
C

#include <stdio.h>
#include <stdlib.h>
int compute(int N) {
int i_0, i_1;
// claim space
double **A = (double **)malloc(sizeof(double *) * N);
for (i_0 = 0; i_0 < N; i_0++) {
A[i_0] = (double *)malloc(sizeof(double) * N);
}
double *x = (double *)malloc(sizeof(double) * N);
double *y = (double *)malloc(sizeof(double) * N);
double *y_sol = (double *)malloc(sizeof(double) * N);
// fill matrix and vector
for (i_0 = 0; i_0 < N; i_0++) {
x[i_0] = i_0 + 1;
y_sol[i_0] = (i_0 + 1) * N;
for (i_1 = 0; i_1 < N; i_1++) {
A[i_0][i_1] = (i_0 + 1.0) / (i_1 + 1.0);
}
}
// for (i_0 = 0; i_0 < N; i_0++){
// printf("[ ");
// for(i_1 = 0; i_1 < N; i_1++){
// printf("%.3f ",A[i_0][i_1]);
// }
// printf("]");
// printf("[ %.1f ] = [ %.1f ][ %.1f ]\n",x[i_0],y[i_0],y_sol[i_0]);
// }
// compute matrix-vector product
for (i_0 = 0; i_0 < N; i_0++) {
y[i_0] = 0;
for (i_1 = 0; i_1 < N; i_1++) {
y[i_0] += A[i_0][i_1] * x[i_1];
}
}
// compare result to solution
double sum = 0.0;
for (i_0 = 0; i_0 < N; i_0++) {
sum += (y[i_0] - y_sol[i_0]) * (y[i_0] - y_sol[i_0]);
}
return sum;
}
int main(int argc, char *argv[]) {
int N;
if (argc != 2) {
N = 1000;
} else {
N = atoi(argv[1]); // Convert the argument to an integer
}
double err = compute(N);
printf("Error for N = %d: %.8f\n", N, err);
return 0;
}